1. The problem statement, all variables and given/known data http://www.astro.uvic.ca/~jwillis/teaching/phys215/phys215_assign_2.pdf It's question 2. 2. Relevant equations Work = U/t E = hf f = c/lambda I=Q/t 3. The attempt at a solution f = c/lambda = (3.00x10^8 m/s)/(530x10^-9 m) = 5.66x10^14 Hz E = hf = (6.626x10^-34 Js)(5.66x10^14Hz) = 3.75x10^-19 J/photon Work = 2.00x10^-3 J/s ----> in one second U = 2.00x10^-3 J #photons = U / E = 5.33 x 10^15 photons #photo-electrons produced = (5.33 x 10^15)/(10^5) = 5.33x10^10 photo-electrons Q = (5.33x10^10)(1.60x10^-19 C) = 8.54x10^-9 C I = 8.54x10^-9 C/s The thing is I did not use the work function of cesium to solve this. Hence I am unsure if this is right... Any help would be appreciated. THANKS!