Photoelectric effect question, help plz, thanks! In the standard experiment the stopping voltage is measured for several wavelengths of incident light. In this apparatus the photocathode is metallic potassium. Suppose that the apparatus has not been used for some time and that its calibration is uncertain. When monochromatic light with a wavelength of 569 nm shines on the potassium surface, the photoelectric current is stopped by a retarding voltage of 0.10 volts. When light with a wavelength of 405 nm is used, the stopping potential is 0.99 volts. a) Determine from these data the value of h/e. This i already got: 4.16862E-15 V*s b) How does the value of h/e determined from these data compare to accepted value? Find the percentage difference between the value value from these data and the accepted value. [ 100·(experiment-accepted)/accepted ] ***I'm stuck here, e.g. what's the accepted value if part a is the experimental value, or is it the other way around, thanks: Can anyone please help me with this part of the problem, thanks yall!!!