# Photoelectric effect

## Homework Statement

Hi there. I have two questions and in both I believe that no photoelectrons will be emitted from the surface.

Question 1

A metal with a work function of 9 x 10^-19 J is irradiated with UV radiation of wavelength 180 mm. Will photoelectrons be emitted from the surface?

## The Attempt at a Solution

E = hf
f = c/λ

E = hc/λ

E = 6.63 x 10^-34 x 1.67 x 10^9
= 1.10 x 10^-24 J

The energy required to release the an electron from the metal is E0 = 9 x 10^-19

Therefore, the energy contained in the light, is insufficient to overcome the forces holding the electron to the surface of the metal.

The second question is that the same metal is used but this time irradiated by 550 nm

I come up with the following - which again indicates that nothing is released.

E = hf
f = c/λ

E = hc/λ

E = 6.63 x 10^-34 x 5.45 x 10^14
= 3.61 x 10^-19 J

Determine the maximum kinetic energy and velocity of any photoelectrons emitted in the above questions. But my calcs indicate that no photoelectrons are emitted. (The electrons rest mass is 9.1 x 10-31 kg.).

For 180nm light, electrons are emitted, you must have made an error in your calculation. I found the photon to have an energy of 1.1x10^(-18) J

For 550nm light, you seem to have done the calculation correctly. No electrons are emitted.

You know that smaller the wavelength, higher the energy of the photon right? How have you managed to calculate an energy for the 180nm light to be 5 orders of magnitude less than that of the 550nm light?

The first question has the wavelength at 180 mm not nanometers. Convert that to meters is 0.18 m.

Cheers

well ok! If thats the case then you're right on that one too... does make asking the electrons kinetic energy redundant. I've never known to be asked about the PE effect for anything other than nm wavelength light, it could be a typo in wherever the question came from and they did in fact mean nm? The whole question would make more sense if this was the case... :D

well ok! If thats the case then you're right on that one too... does make asking the electrons kinetic energy redundant. I've never known to be asked about the PE effect for anything other than nm wavelength light, it could be a typo in wherever the question came from and they did in fact mean nm? The whole question would make more sense if this was the case... :D

Electromagnetic radiation with a wavelength of 180mm would be described as microwave, not ultraviolet! Suspect a typo.

I agree, it does making asking about the kinetic energy redundant - I think it is a typo..

Many thanks for all your help on this one.

well ok! If thats the case then you're right on that one too... does make asking the electrons kinetic energy redundant. I've never known to be asked about the PE effect for anything other than nm wavelength light, it could be a typo in wherever the question came from and they did in fact mean nm? The whole question would make more sense if this was the case... :D