Photoelectric Effect: X-ray, 2 Metals, 5 & 2.3eV Work Function

In summary: If it has more than the 2.3eV difference in work function, then the electron will be liberated. If it has less than that, then it will not be liberated and the x-ray will just pass through the metal.
  • #1
Ekramul Towsif
5
0

Homework Statement


X·ray is produced when an electron is incident on a metal surface with ##2x10^8 ms^-1## velocity
.Applying this X-ray on the surface of two metals having work function of 5 eV and 2.3eV, photoelectric effect is observed.
e by

Homework Equations



The Attempt at a Solution


##E = K_{max} + \phi##
##hf = \frac 1 2mv^2 + hf_o##

i got stucked here. i don't know what to do next
[/B]
 

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  • #2
Your post is difficult to read, and confused. Could you more accurately produce the question as it was asked?
 
  • #3
Cutter Ketch said:
Your post is difficult to read, and confused. Could you more accurately produce the question as it was asked?
which part or portion is difficult to undestand ?
 
  • #4
Ekramul Towsif said:
which part or portion is difficult to undestand ?

Well this is very interesting. I would have quoted the confused questions in the OP: the lack of a part a or b, the fact that part d was neither a sentence nor a question nor in fact an intelligible phrase, but it appears you've edited the post. Now there are no questions at all and you've pasted in a picture of your problem. Now here's the interesting part. Although better than the OP, the question as given to you is pretty confused. I presume that whoever wrote it speaks something other than English as a first language. Ok, well let's see what we can do.

From your unedited OP I presume you've answered a and b. For c you posted an energy equation which appears to be for scattering in that there is an h f0. Here there is no h f0. The electron does not necessarily have to give all of its energy to a single X-ray, but that is the most it can do, so I think that is what they want you to assume. So what is the frequency of the x-ray if all of the kinetic energy of the electron produces one x-ray photon?

The last part seems to be asking if that frequency of an X-ray can liberate an electron given the two work functions. Well, does it have enough energy?
 

1. What is the photoelectric effect?

The photoelectric effect is a phenomenon in which certain metals emit electrons when exposed to electromagnetic radiation, such as X-rays. This effect was first observed by Heinrich Hertz in 1887 and later explained by Albert Einstein in 1905.

2. What is the significance of X-rays in the photoelectric effect?

X-rays have a high energy and short wavelength, making them ideal for studying the photoelectric effect. When X-rays strike a metal surface, they can cause electrons to be ejected from the metal, producing a measurable current.

3. How do the work functions of 2 metals affect the photoelectric effect?

The work function is the minimum energy required to remove an electron from the surface of a metal. In the photoelectric effect, the work function of a metal determines the threshold frequency of the incident light needed to eject electrons from the metal surface.

4. What is the relationship between the energy of the incident light and the work function of a metal?

According to the photoelectric effect, the energy of the incident light must be equal to or greater than the work function of the metal in order to eject electrons. This relationship is described by the equation: E = hf = Φ + KE, where E is the energy of the incident light, h is Planck's constant, f is the frequency of the light, Φ is the work function, and KE is the kinetic energy of the ejected electron.

5. How does the energy of the incident light affect the kinetic energy of the ejected electrons?

The energy of the incident light determines the kinetic energy of the ejected electrons. If the energy of the incident light is greater than the work function of the metal, the excess energy will be converted into kinetic energy of the electrons. However, if the energy of the incident light is equal to the work function, the electrons will only have enough energy to be ejected from the surface but will not gain any additional kinetic energy.

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