What is Photon Momentum and hf?

In summary, when a photon is absorbed by an electron in an atom, the electron gets excited and re-emits the energy in the form of a photon. This process is continuous when the atom is hit by a continuous laser beam, and the photons are emitted in no preferred direction, resulting in an average reaction momentum of zero. The atom moves when absorbing the photon due to the momentum of the photon being absorbed, and this momentum is what moves the atom. Energy and momentum are both conserved in this process, and the emitted radiation can have a different frequency than the laser beam, depending on the motion of the atom. When considering a single atom in a vacuum, the energy and momentum transfer from the photon to the atom can be calculated using the
  • #1
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i was learning about laser cooling in thermodynamics, and my professor said that as the photon gets absorbed by the electron, the electron gets excited and re-emits the energy in the form of a photon, and that this process was continuous since it's getting hit by a continuous laser beam and that the emission process emitted the photons in no preferred direction so the average reaction momentum (the kickback momentum from emitting the photon one way) is zero. He said that the atom moved when absorbing the photon since the photon has momentum and it is this momentum that is being absorbed that moves the atom. (we were just talking about what happened for a single atom in a vacuum being hit by a continuous laser beam of the appropriate wavelength)we have went back and forth various times now via email and i am still completely lost. The photon has energy hf. This gets absorbed by the electron so this particular quantity went into exciting the electron into a higher potential orbital. But now there is a momentum component that gets transferred.

What?

i thought the energy of a photon was hf. and all of this went into exciting the photon. if the acceleration/propelling of the atom came from the photon, the photon MUST have an additional energy component, because it takes energy to do so. I'm trying to avoid using momentum and I'm trying to put everything in terms of energy; it's just easier for me to keep track of everything when all the stuff I'm dealing with are in the same forms (energy) (yes i understand I'm not dealing with just a single energy form, i was just referring to the fact that i don't have a mix of an energy term, amomentum term, a torque term, a moment of inertia term, etc etc etc...). So my professor said that there is a momentum component that gives rise to the acceleration of the atom. I tried converting this 'momentum piece' in terms of energy and i asked him if then, the TRUE energy of a photon is hf+(1/2)pc

and he replied that it was not. I am still at a loss... where is the energy to accelerate the atom coming from? If all of the hf did go into exciting the electron, then there must be another/more energy term/s that i am not aware of. What are they?

thanks
 
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  • #2
the electron gets excited
A single electron cannot get excited. An atom with electrons can.
and that this process was continuous
Well, it happens frequently.

But now there is a momentum component that gets transferred.
A photon has energy E=hf and momentum p=E/c = hf/c.

and all of this went into exciting the photon.
The atom?
Depending on the velocity of the atom, the photon appears a bit red- or blueshifted for the atom. Therefore, its energy is not exactly the same. Anyway, energy is not the relevant quantity here. You can just consider momentum, this is easier.

where is the energy to accelerate the atom coming from?
The emitted radiation does not have to have the same frequency as your laser beam. This depends on the motion of the atom and the direction of the emitted radiation. Doppler effect...
 
  • #3
i mentioned that we were only dealing with a single atom in an ideal vacuum because i wanted an ideal scenario. I guess i left out one piece; I will also mention that i will be ignoring doppler shifting and just considering an initially stationary atom relative to the container. (i'm trying to get an ideal scenario because i want to understand the fundamental mechanism before i start considering six laser beams and the doppler shift.)

i was told that the average momentum from the emitted radiation just cancels out because the electron radiates in all directions equally; if this is true then i am not concerned with the emitted radiation.

I am only concerned with the mechanism of propagation of the atom from the photon. ie the 'momentum' transfer. And i am still confused as to where exactly the energy that went into moving the atom came from if the total energy of the photon is hf. i cannot say that "p=hf/c therefore the momentum transferred is hf/c". otherwise i would be violating energy conservation wouldn't i? i already used "hf" to excite the electron (in the atom...). and as I've said if i have any more energy to something into motion, then the total energy of a photon should be something more than just hf.

Anyway, energy is not the relevant quantity here. You can just consider momentum, this is easier.

if i am considering a stationary atom, and not considering doppler shift, is energy still irrelevant? if so, why? whenever something has momentum it has to have kinetic energy doesn't it?
 
  • #4
A photon has both energy and momentum, and so does an atom. When an atom absorbs a photon both the energy and the momentum are conserved together. The atom's final energy equals the total energy of the initial atom and the photon together. The atom's final momentum equals the vector sum of the momenta of the initial atom and photon.
 
  • #5
I'm pretty sure the OP's complaint is that photon had to have energy to excite the electron and also do work on the atom.

And that is absolutely correct. The absorption spectrum of the atom is going to be shifted due to recoil, which is going to account for the difference in energy. In other words, if you send a photon at a still atom, the photon has to be slightly more "blue" than the actual absorption wavelength of the atom to account for the extra work required to accelerate the atom.
 

1. What is photon momentum?

Photon momentum refers to the measure of the momentum of a photon, which is a particle of light. It is calculated by multiplying the photon's frequency (f) by Planck's constant (h) and dividing the product by the speed of light (c). The unit of photon momentum is kilogram meters per second (kg·m/s).

2. How is photon momentum related to the photon's energy (hf)?

The energy of a photon (hf) and its momentum are directly proportional, meaning that as the energy of a photon increases, so does its momentum. This is because the frequency (f) and energy (E) of a photon are also directly proportional, with E = hf. Therefore, the higher the frequency of a photon, the higher its energy and momentum.

3. Can photons have negative momentum?

No, photons cannot have negative momentum. According to the laws of physics, momentum is always a positive quantity. Since the speed of light (c) is a constant and cannot be negative, the frequency (f) and energy (hf) of a photon are also positive. Therefore, the momentum of a photon will always be positive.

4. How does photon momentum relate to the wave-particle duality of light?

The concept of photon momentum is one of the key pieces of evidence for the wave-particle duality of light. On one hand, photons behave like particles with a definite momentum, as demonstrated by the photoelectric effect. On the other hand, they also exhibit wave-like properties, such as diffraction and interference. This duality is explained by the wave-particle nature of light, where photons can behave as both particles and waves depending on the experimental setup.

5. Why is photon momentum important in the field of quantum mechanics?

Photon momentum plays a crucial role in quantum mechanics, as it helps explain the behavior of particles at the microscopic level. In quantum mechanics, particles can exhibit behaviors that are not observed in classical mechanics, such as wave-particle duality and quantum tunneling. Understanding the momentum of photons is essential in understanding these quantum phenomena and developing theories and technologies based on them.

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