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Photon polarization.

  1. May 7, 2013 #1
    So I know that a linearly polarized photon is in a state

    [itex]ψ = cos(θ)\left|x\right\rangle + sin(θ)\left|y\right\rangle[/itex]

    What if θ depends on time maybe something like [itex]θ\equiv\frac{E_{0}t}{\hbar}[/itex]? The polarization is linear at any time t, it rotates as time passes? Isn't that circular polarization? What's the difference between the states?

    This is my attempt at an explanation:

    Is it correct to say that the polarizations photons in the state I'm describing rotate as they move through time, and circularly polarized photons (in a time independent state) rotate as they move through space?

    I think this would imply that if I put my photons on a polarizer and measure the intensity, it would oscillate with a frequency [itex]ω=\frac{E_{0}}{\hbar}[/itex]

    Let me know if this is sound physics.
     
  2. jcsd
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