So I know that a linearly polarized photon is in a state(adsbygoogle = window.adsbygoogle || []).push({});

[itex]ψ = cos(θ)\left|x\right\rangle + sin(θ)\left|y\right\rangle[/itex]

What if θ depends on time maybe something like [itex]θ\equiv\frac{E_{0}t}{\hbar}[/itex]? The polarization is linear at any time t, it rotates as time passes? Isn't that circular polarization? What's the difference between the states?

This is my attempt at an explanation:

Is it correct to say that the polarizations photons in the state I'm describing rotate as they move through time, and circularly polarized photons (in a time independent state) rotate as they move through space?

I think this would imply that if I put my photons on a polarizer and measure the intensity, it would oscillate with a frequency [itex]ω=\frac{E_{0}}{\hbar}[/itex]

Let me know if this is sound physics.

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# Photon polarization.

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