Photon polarization.

1. May 7, 2013

wotanub

So I know that a linearly polarized photon is in a state

$ψ = cos(θ)\left|x\right\rangle + sin(θ)\left|y\right\rangle$

What if θ depends on time maybe something like $θ\equiv\frac{E_{0}t}{\hbar}$? The polarization is linear at any time t, it rotates as time passes? Isn't that circular polarization? What's the difference between the states?

This is my attempt at an explanation:

Is it correct to say that the polarizations photons in the state I'm describing rotate as they move through time, and circularly polarized photons (in a time independent state) rotate as they move through space?

I think this would imply that if I put my photons on a polarizer and measure the intensity, it would oscillate with a frequency $ω=\frac{E_{0}}{\hbar}$

Let me know if this is sound physics.