Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Photonic local density of states and field intensity

  1. Mar 18, 2015 #1
    Dear All:

    I'm very confusing with the relationship between photonic local density of states and the field intensity. In thermal equilibrium, the field intensity should be proportional to the photon's number (or squared) and also be proportional to the local density of states. We know that this density of states is proportional to the n^3, where n is the refractive index. Meaning if you have larger n, you should have larger field intensity. But actually it's not. If you have larger n, meaning you have larger dielectric function, the dielectric screening will be stronger. Under a same excitation, you should have smaller field intensity.

    How to under stand this point?
     
  2. jcsd
  3. Mar 23, 2015 #2
    Thanks for the post! This is an automated courtesy bump. Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Photonic local density of states and field intensity
  1. Photon state (Replies: 1)

Loading...