1. Mar 11, 2009

### MaryJane101

A 0.5 kg ball initially at rest is subject to three forces:
1. F1 has a magnitude equal to 5.0 N and points 36.9 degrees above the horizontal direction (relative to the positive x direction),
2. F2 has a magnitude equal to 2.0 N and points to the left (negative x direction),
3. F3 has a magnitude equal to 4.0 N and points straight down (negative y direction).

Given these forces, answer the following questions:
a. Draw a free-body diagram showing the forces acting on the ball. Be sure to draw
vectors with the correct lengths. Determine the x- and y-components of each force
and label those values on your diagram.
b. Calculate the x- and y-components of the net force acting on the ball.
c. Calculate the x- and y-components of the ball’s acceleration.
d. Calculate the total distance traveled by the ball after 3.0 s.

2. Mar 11, 2009

### Ofey

At what point do you get stuck?

3. Mar 11, 2009

### wesDOT

Are you familiar with unit vectors?

4. Mar 11, 2009

### MaryJane101

I dont even know where to begin this is all new to me

5. Mar 14, 2009

### MaryJane101

i got the free body drawing but how do i do part b c d ?

6. Mar 15, 2009

### Redbelly98

Staff Emeritus
For part b, you'll need to apply trig functions (sin and cos) to the forces you drew, using the angle of each of the 3 forces.

Also, keep in mind that:
Horizontal forces (acting to the left or right) act in the +x or -x direction -- there is no y-component.
Vertical forces (up or down) act in the +y or -y direction -- there is no x-component.

Surely there is an example worked out in your text book or class lecture notes?