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Physical pendulum hoop

  1. Nov 29, 2009 #1
    1. The problem statement, all variables and given/known data

    a hoop of radius R=.18m and mass=.44kg is suspended by a point on its perimeter. If the hoop is allowed to oscillate side to side, what is the period of oscillation?

    2. Relevant equations

    I=MR^2 plus an offset? MR^2
    so I=2(MR^2)?
    PE=1/2kx^2
    w=(2pi)/T
    KErot=1/2Iw^2
    3. The attempt at a solution
    I=2(MR^2)
    I=2(.44)(.18^2)
    I=.028512
    PEi=KErotfinal
    mgh=1/2Iw^2
    (.44)(9.8)(.36)=1/29.o28512)w^2
    10.43498=w
    10.43498=(2pi)/T
    T=.60213s
     
  2. jcsd
  3. Nov 29, 2009 #2
    find I and plug it into T=2pi(sqrtof I/(mgx)?
     
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