What Is the Period of Oscillation for a Hoop Suspended by Its Perimeter?

In summary, a physical pendulum hoop is a type of pendulum consisting of a circular hoop that can freely rotate around a fixed axis. It works by converting potential energy into kinetic energy and back again, with its period of oscillation being affected by factors such as length, mass, and point of suspension. The moment of inertia for a physical pendulum hoop can be calculated using a specific equation, and it has various real-world applications in timekeeping, sports equipment, and physics experiments.
  • #1
writelu
2
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Homework Statement



a hoop of radius R=.18m and mass=.44kg is suspended by a point on its perimeter. If the hoop is allowed to oscillate side to side, what is the period of oscillation?

Homework Equations



I=MR^2 plus an offset? MR^2
so I=2(MR^2)?
PE=1/2kx^2
w=(2pi)/T
KErot=1/2Iw^2

The Attempt at a Solution


I=2(MR^2)
I=2(.44)(.18^2)
I=.028512
PEi=KErotfinal
mgh=1/2Iw^2
(.44)(9.8)(.36)=1/29.o28512)w^2
10.43498=w
10.43498=(2pi)/T
T=.60213s
 
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  • #2
find I and plug it into T=2pi(sqrtof I/(mgx)?
 
  • #3


I would like to first point out that the equation for the moment of inertia of a hoop is actually I=MR^2, without the additional offset term. This error may have led to the incorrect calculation of the moment of inertia in the attempted solution.

To find the period of oscillation, we can use the equation T=2pi*sqrt(I/mgh), where I is the moment of inertia, m is the mass, g is the acceleration due to gravity, and h is the distance from the point of suspension to the center of mass. In this case, h=R/2.

Substituting the given values, we get T=2pi*sqrt(2(.44)(.18^2)/(.44)(9.8)(.18/2))=0.596s.

Therefore, the period of oscillation for the given physical pendulum hoop is approximately 0.596 seconds.
 

What is a physical pendulum hoop?

A physical pendulum hoop is a type of pendulum that consists of a rigid, circular hoop that is free to rotate about a fixed axis. It is commonly used in physics experiments to study oscillations and determine properties such as the moment of inertia and period of oscillation.

How does a physical pendulum hoop work?

A physical pendulum hoop works by converting potential energy into kinetic energy and back again as it oscillates. When the hoop is displaced from its equilibrium position, it experiences a restoring torque due to gravity and begins to swing back and forth. The period of oscillation depends on the physical characteristics of the hoop, such as its mass and moment of inertia.

What factors affect the period of a physical pendulum hoop?

The period of a physical pendulum hoop is affected by several factors, including the length of the hoop, the mass of the hoop, and the point of suspension. The period is also affected by external factors such as air resistance and friction, which can slow down the motion of the hoop.

How is the moment of inertia calculated for a physical pendulum hoop?

The moment of inertia for a physical pendulum hoop can be calculated using the equation I = mR2, where I is the moment of inertia, m is the mass of the hoop, and R is the radius of the hoop. This equation assumes that the hoop is a thin, uniform ring with all of its mass concentrated at the outer edge.

What are some real-world applications of a physical pendulum hoop?

Physical pendulum hoops have a variety of real-world applications, including in the design and construction of clocks and other timekeeping devices. They are also used in sports equipment, such as hula hoops and gymnastics rings. In addition, physical pendulum hoops are used in physics and engineering experiments to study oscillations and rotational motion.

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