1. The problem statement, all variables and given/known data A physical pendulum consists of a meter stick that is pivoted at a small hole drilled through the stick a distance d from the 50 cm mark. The period of oscillation is 2.5 s. Find d 2. Relevant equations T=2PI*sqrt(I/mgh) I(com)=(1/2)mL^2 parallel axis theorem I=I(com)+m(L/2-d)^2 L=length of stick h=L/2=center of mass 3. The attempt at a solution so T=2.5 s center of mass = .50 m I=(1/2)mL^2 + m*(L/2-d)^2 then plug T, I, and h in for the equation T=2PI*sqrt(I/mgh) 2.5 s=2PI*sqrt((3L^2/4-2Ld+d^2)/(gL/2)) however when I solve for d I do not get 5.6 cm..anyone see my mistake?