(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A physical pendulum consists of a meter stick that is pivoted at a small hole drilled through the stick a distance d from the 50 cm mark. The period of oscillation is 2.5 s. Find d

2. Relevant equations

T=2PI*sqrt(I/mgh)

I(com)=(1/2)mL^2

parallel axis theorem

I=I(com)+m(L/2-d)^2

L=length of stick

h=L/2=center of mass

3. The attempt at a solution

so T=2.5 s

center of mass = .50 m

I=(1/2)mL^2 + m*(L/2-d)^2

then plug T, I, and h in for the equation

T=2PI*sqrt(I/mgh)

2.5 s=2PI*sqrt((3L^2/4-2Ld+d^2)/(gL/2))

however when I solve for d I do not get 5.6 cm..anyone see my mistake?

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# Homework Help: Physical pendulum oscillation

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