Physics 11 help please ?

  • Thread starter roxxyroxx
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  • #1
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Homework Statement



A 55 kg student wearing skates stands at rest on a frictionless horizontal ice surface. She throws a 10 kg backpack horizontally with a speed8.3 m/s .
What is the velocity of the student after she throws the backpack?

Homework Equations



F[tex]\Delta[/tex]t = m[tex]\Delta[/tex]v

The Attempt at a Solution


so the answer should be 1.5 m/s [N] and i got this by dividing 10 kg (backpack) by 55 kg (student) and then multiplying that answer by 8.3 m/s . is this the right way or is there a proper formula i should follow?
thanks !
 

Answers and Replies

  • #2
Doc Al
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That's correct. The impulse given to the backpack will be exactly equal and opposite to the impulse given to the student. Thus:
mstudent*vstudent = mbackpack*vbackpack

Just solve for vstudent.
 
  • #3
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great, thanks ! :smile:
 

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