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Physics 11 help

  1. Jul 9, 2007 #1
    1. The problem statement, all variables and given/known data

    If the force of gravity(weight) of a 1.2kg textbook were to be measured at various distances (d) from the Earth's center, the data would appear as follows:

    1) 11.8
    2) 5.21
    3) 1.9
    4) 1.0

    1) 6.4 x 10^6
    2) 9.6 x 10^6
    3) 16 x 10^6
    4) 22 x 10^6

    B) Find the distance, d, at which the gravitational force on the book is 8.0 kg*m/s^2

    3. The attempt at a solution

    I'm struggling with physics here...

    I'm not entirely sure what my equation should be and why. Is it

    F(force) = k(constant) / d(distance)^2


    if so then all I need to do is find k and I can do that correct? but how exactly do I get k.

    When I graph the inverse of the square I get a relatively straight line and the table looks like this

    Force data stays the same

    1) 24.4 x 10^-15
    2) 10.9 x 10^-15
    3) 3.9 x 10^-15
    4) 2.1 x 10^-15

    so.. to find k do I go..

    (11.8 - 1.0) / [(24.4 x 10^-15)-(2.1 x 10^-15)]

    which on my calculator is 4.843049327 x 10^14 and then plug it into the equation for k and plug in8.0kg*m/s^2 for F and solve for d?

    also how do I deal with the units when finding k?

    or do I leave out the x 10's and just have 24.4 - 2.1? or am I doing that totally wrong?

    How does the weight of the book(1.2kg) come into play here in the equation? or does it?

    I'm having troubles understanding why I'm doing what I'm doing in these questions I've been given, which isn't making things easier.

    Thank you for any help you can provide, I have another question as well but am not sure if I should post 2 separate posts or combine the 2 different questions in the same post?

    - Otis
  2. jcsd
  3. Jul 10, 2007 #2


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    Staff Emeritus
    Science Advisor

    Yes, this is correct.

    Ok, so have you plotted the graph F vs. d-2?

    If the graph is what I have guessed, then this is the correct way of finding the gradient (which is k in this case.)
    I'm not sure what you mean by this.
    No, you were correct above.

    The mass(!) of the book comes into play in the constant k. Since it is the same every time, we just put this in the value of k. If you are interested, the general law for the gravitational force is [tex]F=\frac{Gm_1m_2}{r^2}[/tex] where G is called the gravitational constant and m_1 and m_2 will be masses of the book and the earth.

    It depends whether the questions are related or not. Either way, you should probably try and finish one problem before attempting another.
  4. Jul 11, 2007 #3
    Thank you, I ended up figuring it all out before seeing this but I appreciate the reply!
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