# Physics 11

Use the mirror equation to find the image location and the height of an object placed at the centre of curvature of a concave mirror. Also find the magnification. Hint: What is the relation between the focal length and the object distance, do, for this situation?

Chi Meson
Homework Helper
What's the mirror equation? (It's the same as the thin-lens equation)

What's the relationship between the center of curvature and the focal point?

centre of curvature is half the focal point and the mirror equation is 1/di + 1/do = 1/f

but i still don't understand how that answers the question..

Chi Meson
Homework Helper

Center of curvature is not half the focal length, it's the other way 'round.

Center of curvature is twice the focal length. So focal length is "f" and the object distance is "2f." Do a little algebra and find the image.

Would the focal length be equal to the object distance?

Chi Meson
Homework Helper
Would the focal length be equal to the object distance?

No, try again. You're close.

But I have to go now, keep at it.