Physics 11

  • Thread starter nitegrl
  • Start date
  • #1
1
0
Hi I'm new here, I hope someone can help me. I think I got the first half of the question, but I got stuck one the second part. Well here it goes,

A force of 40N accelerates a 5.0kg block at 6.0m^2 along a horizontal surface.
a.) How large is the friction force?
b.) What is the coefficient of friction?

a.) Fnet= ma
Fp-Ff= ma
(40)-Ff= (5)(6)
40-Ff= 30
40-30= Ff
Ff= 10N

I know that you have to use Ff= (mu)Fn, but how do you get Fn?

And is there a way to show symbols like mu?
 

Answers and Replies

  • #2
382
2
Since the block moves in the horizontal direction only, the sum of the vertical forces equals zero. that is how you get fn.
type to get the symbol.
[tex]\mu[/tex]
 
  • #3
1,015
1
[tex]fn=mg=9.8*5*\mu[/tex]
[tex]10=49\mu[/tex]
[tex]\mu=.2[/tex]

does this seem right? its been awhile
 

Related Threads on Physics 11

  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
8
Views
1K
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
6
Views
677
  • Last Post
Replies
3
Views
1K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
4
Views
1K
  • Last Post
Replies
1
Views
853
Top