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Physics 11

  1. Oct 19, 2004 #1
    Hi I'm new here, I hope someone can help me. I think I got the first half of the question, but I got stuck one the second part. Well here it goes,

    A force of 40N accelerates a 5.0kg block at 6.0m^2 along a horizontal surface.
    a.) How large is the friction force?
    b.) What is the coefficient of friction?

    a.) Fnet= ma
    Fp-Ff= ma
    (40)-Ff= (5)(6)
    40-Ff= 30
    40-30= Ff
    Ff= 10N

    I know that you have to use Ff= (mu)Fn, but how do you get Fn?

    And is there a way to show symbols like mu?
  2. jcsd
  3. Oct 19, 2004 #2
    Since the block moves in the horizontal direction only, the sum of the vertical forces equals zero. that is how you get fn.
    type to get the symbol.
  4. Oct 20, 2004 #3

    does this seem right? its been awhile
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