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Physics 20

  1. Apr 18, 2010 #1
    1. The problem statement, all variables and given/known data

    a force of 15 N {south} moves a case weighing 40 N { down} across a level surface at constant velocity. what is the coefficient of kinetic friction for the cae on the counter

    2. Relevant equations
    Force of friction = the coefficient of friction(μ) x normal force


    3. The attempt at a solution

    Force of friction = the coefficient of friction (μ )x normal force
    55N= μ x 55
    =1
     
    Last edited: Apr 18, 2010
  2. jcsd
  3. Apr 18, 2010 #2
    If the case is moving at constant velocity, then the force of friction must exactly equal the applied force.
     
  4. Apr 19, 2010 #3
    thank you. :)
     
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