Mary left home at noon running at 7m/s towards school. Her brother John left 35 seconds later running at 8m/s. How much time passed and how far were they from the house when John caught up to Mary. 2. Relevant equations My solution i tried was to the x-y graph. My notes saids im supposed to use these formulas d-d0=vt , d=vt 3. The attempt at a solution I tried graphing as an university friend/student has told me but it just doesnt work out because when I get to john i have no clue to where i start on the graph to graph johns distance. All i know right now is that in 35 seconds, when john leaves Mary is at 245 metres.