Two balls of equal mass collide and stick together as shown in the figure. The initial velocity of ball B is twice that of ball A. (Take θ = 56°.)
(a) Calculate the angle above the horizontal of the motion of mass A + B after the collision.
(b) What is the ratio of the final velocity of the mass A + B to the initial velocity of ball A, vf/vA?
(c) What is the ratio of the final energy of the system to the initial energy of the system, Ef/Ei?
The Attempt at a Solution
a) x= m ( 2vcos(56) + vcos(56) ) = 2mVfx
2vcos(56) + vcos(56)= mvfx
y = m ( 2vsin(56) + vsin(56) ) = 2mVfy
2vsin(56) + vsin(56) = 2mVfy
Am I suppose to take the magnitude of this ? How do I solve for two unknowns ?
Do all the m's and v's cancel out?