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Physics Energy Problem Help

  1. Feb 10, 2012 #1
    1. The problem statement, all variables and given/known data
    Part 1. A 2.25 × 10^3 kg car requires 5.8 kJ of work to move from rest to some final speed. During this time, the car moves 29.8 m.
    Neglecting friction, find a) the final speed. Answer in units of m/s

    Part 2.
    b.)the net horizontal force exerted on the car. Answer in units of N

    2. Relevant equations
    For Part 1. I did 5800j=1/2mv^2 plugged in and got 2.2705848, which is correct
    For Part 2 I guess it would be W=fdcos?
    3. The attempt at a solution
    For Part 1. I did 5800j=1/2mv^2 plugged in and got 2.2705848, which is correct
    For part 2 I did 5800=fdcos but i am confused on what they mean by saying net.
     
  2. jcsd
  3. Feb 10, 2012 #2

    wukunlin

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    Gold Member

    net force just means the vector sum of forces when different forces are applied to an object
     
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