# Physics equation

1. Nov 2, 2006

### amoateng

6,0 * 10^-9 = 2pi*√(m/80)

i thought it would be something llike :
6*10^-9 = 2pi*√(m/80)
(6*10^-9)/(2pi) = √(m/80)
[(6*10^-9)^2]/(4pi^2)= m/80
m = 80*[(6*10^-9)^2]/(4pi^2)

Last edited: Nov 2, 2006
2. Nov 2, 2006

### Staff: Mentor

I moved this to the Homework section. And omoateng, you need to show some work in order to get our help. We are not an answer engine that you type questions into.

What steps should you take to isolate m in the equation?

EDIT -- the OP added some work to his first post...I'll try to answer below.

Last edited: Nov 2, 2006
3. Nov 2, 2006

### Staff: Mentor

Just type your final line into your calculator again. I get that correct answer with my calculator and your final line. If you aren't using an RPN calculator, be careful how you handle the intermediate results. You did the algebra correctly.

4. Nov 2, 2006

### Matthew Rodman

I get

$$m = \frac{72}{\pi^2} .10^{-17}$$

which pretty much equals 7.3x10^-17, as far as I can tell.

edit: note, this is equal to your answer for m (just expressed differently)

Last edited: Nov 2, 2006