# Physics equilbirium

1. Jan 20, 2009

### key

a person stands a distance of 0.300 meters from the right end of a 2.00 meter long uniform platform that is supported by two posts, one at each end. The board has a mass of 20.0 kg and the person's mass is 75.0 kg.

a. determine the force exterted on the board by the post on the left end.

b. determine the force exerted on the board by the post on the right end.

Sum moments about any point. I will choose the Right end.

-.3*75g -1*20g+Fleft*2=0

That gives you Fleft end.

Now, sum forces vertically
Fleft+Fright-20g-75g=0
solve for fright.

i don't think i'm doing it right
can someone help

2. Jan 20, 2009

Hi key, well I think you simply over complicated things actually, have a look back at you first equation, isn't that already solvable, you did exactly the right thing by taking moments about the right post you eliminated the right reactive force from you equations leaving you with a single variable :D which is solvable on its own, and repeat to find the right hand force, hope that helps :D

3. Jan 20, 2009

### PhanthomJay

As Galadirith has noted, you can sum moments about the left post to solve for F-right, and then this serves as a check for your value you obtained for F_right when you summed forces in the y direction, which is also correct. It's good to have a backup equation for a check; if the value obtained for F_right is different when using the sum of moment equation than it is when using the sum of forces equation, you made an error somewhere.

4. Jan 20, 2009

### key

I got 21.25 for F left and -73.75 for F right.
Is that right?

5. Jan 21, 2009