A ladder weighing 200N is being held by a man. The man shoulder acts as a pivot. His arm is pushing an upward force F.
Where could a weight of 150N be hang upon, so that force F do not need to counteract the weight of the ladder
Moment= F x Perpendicular Distance
The Attempt at a Solution
I am not sure if I am understanding it correctly. If I am not wrong, the question is asking me, where can I hang a weight of 150N, so that force F no need to counteract the weight of the ladder. Meaning, assume force F = 0N.
Let the distance be x
Total clockwise moment = total anti clockwise moment
150x = 200*0.5
150x = 100
x = 2/3
Therefore it needs to be hang 0.667m away from the pivot or at 3.167m of the ladder.
Am I understanding this correctly?