- #1

- 12

- 0

## Homework Statement

A ladder weighing 200N is being held by a man. The man shoulder acts as a pivot. His arm is pushing an upward force F.

http://i.imgur.com/dMrcRtK.jpg

Where could a weight of 150N be hang upon, so that force F do not need to counteract the weight of the ladder

## Homework Equations

Moment= F x Perpendicular Distance

## The Attempt at a Solution

I am not sure if I am understanding it correctly. If I am not wrong, the question is asking me, where can I hang a weight of 150N, so that force F no need to counteract the weight of the ladder. Meaning, assume force F = 0N.

Let the distance be x

Total clockwise moment = total anti clockwise moment

150x = 200*0.5

150x = 100

x = 2/3

= 0.667m.

Therefore it needs to be hang 0.667m away from the pivot or at 3.167m of the ladder.

Am I understanding this correctly?

Last edited: