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Homework Help: Physics Help ! 1 and 2D motion

  1. Jul 3, 2013 #1
    1. The problem statement, all variables and given/known data
    A ball rolling with an initial velocity of 40m/s[W] undergoes an acceleration of 5.0m/s2[N] for a period of 6.0 seconds. What is the displacement of the ball in the 6.0 seconds?

    3. The attempt at a solution

    Apparently the answer is 260m[W21°N]

    Please help!
    Last edited: Jul 3, 2013
  2. jcsd
  3. Jul 3, 2013 #2
    PF rule. No attempt means no help.
  4. Jul 3, 2013 #3


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    Science Advisor

    Do you not know any formulas relating constant acceleration to speed and distance?
  5. Jul 3, 2013 #4
    Well I know the displacement north is 30m, because i was given an acceleration and a time. From that I found the final velocity of 50m/s from the triangle these two velocities created. Using the motion formula V22 = V12 + 2ad , i found the displacement to be 90, not 260... And I have no idea how to use vectors in this case to find a direction
  6. Jul 4, 2013 #5
    You have to use vectors in this case. Or just find the x-direction motion separately and y-direction displacement separately. Then add those two Vectorially by forming triangle as you did to final velocity. Hope you find this helpful.
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