Physics (help appreciated)

  • Thread starter blackout85
  • Start date
  • #1
28
1
A current of 0.3 A is passed through a lamp for 2 minutes using a 6 V power supply. The electrical energy dissipated by this lamp during the two minutes is:
a) 1.8 J
b) 12 J
c) 20J
d) 36 J
e) 216 J

If someone could just help me to start off that would be great.
The main equations I have to use are

I=Q/t
E= QV

(.3A)= (Q)/(120)
Q= 36

E= (36)(6V)
E=216 J

Am I right:confused:
 

Answers and Replies

  • #2
960
0
looks good, tho ordinarily the power/heat would first be calculated as I*V, then multiplied by 120
 

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