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Physics help - finding what slope means

  1. Oct 11, 2005 #1
    Suppose a student is given position-time data for a cart which was known to have an initial velocity of zero. if the student plots the fifth root of time (t^1/5) on the y axis, what variable should he plot on the x axis so that the resulting graph is a straight line? how is the slope of the line related to the acceleration of the cart?
    [tex]d = \frac{1}{2}at^2[/tex]
    [tex]d^\frac{1}{10} = (\frac{1}{2}a)^\frac{1}{10} t^\frac{1}{5}[/tex]

    this is what i've done so far.... can anyone give me some hints as to what to do next?
     
  2. jcsd
  3. Oct 17, 2005 #2

    Tom Mattson

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    Sorry for the late reply.

    * Get [itex]t^{1/5}[/itex] by itself.
    * Identify the independent variable (the one that is plotted on the x-axis).
    * Identify the slope.

    This can be done by comparing your equation to the equation [itex]y=mx[/itex] after you solve for [itex]t^{1/5}[/itex].
     
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