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Physics help (Kinetic Energy)

  • Thread starter foxcub156
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  • #1
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Homework Statement


A bead with mass (1.8x10^-2)kg is moving along a wire in the positive direction of an x axis. Beginning at time=0, when the bead passes through x=0 with speed 12m/s, a constant force acts on the bead, the picture indicates the bead's position at these four times: t0=0 sec., t1=1.0 sec., t2=2.0 sec., t3=3.0 sec., The bead momentarily stops at t=3.0 sec. What's the kinetic energy of the bead as t=10 sec?


Homework Equations


K=(.5)mv^2

vf^2=vi^2+2ad


The Attempt at a Solution



Is the answer K=1.296? I really think it's wrong.
 

Answers and Replies

  • #2
That seems to be the initial KE, If under constant force it took 3 seconds to stop, what will the velocity be after 10s?
 

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