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Physics help (Kinetic Energy)

  1. Nov 27, 2011 #1
    1. The problem statement, all variables and given/known data
    A bead with mass (1.8x10^-2)kg is moving along a wire in the positive direction of an x axis. Beginning at time=0, when the bead passes through x=0 with speed 12m/s, a constant force acts on the bead, the picture indicates the bead's position at these four times: t0=0 sec., t1=1.0 sec., t2=2.0 sec., t3=3.0 sec., The bead momentarily stops at t=3.0 sec. What's the kinetic energy of the bead as t=10 sec?


    2. Relevant equations
    K=(.5)mv^2

    vf^2=vi^2+2ad


    3. The attempt at a solution

    Is the answer K=1.296? I really think it's wrong.
     
  2. jcsd
  3. Nov 27, 2011 #2
    That seems to be the initial KE, If under constant force it took 3 seconds to stop, what will the velocity be after 10s?
     
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