The problem involves a roller coaster car moving over the top of a circular rise with a radius of 18 meters. The scenario describes the passengers feeling lighter, with an apparent weight of only 60% of their true weight, prompting a question about the speed of the coaster at that point.
The discussion has seen various attempts to clarify the problem, with some participants providing guidance on applying Newton's second law for circular motion. There is an acknowledgment of a misunderstanding regarding the forces involved, and one participant indicates they have resolved their confusion regarding the calculations.
Participants note that the problem is situated within an introductory physics context, and there is a suggestion to focus on the net forces acting on the passengers at the top of the hill. Some participants express uncertainty about the calculations and the setup of the problem.
You did not calculate what the question asks.SilverAu said:Homework Statement
A roller coaster car is going over the top of a 18-m- radius circular rise. At the top of the hill, the passengers "feel light," with an apparent weight only 60% of their true weight. How fast is the coaster moving?
Homework Equations
I think F=mv^2/ (r)
F=ma
The Attempt at a Solution
Attempt:
F=mv^2/r
(.6)g=v^2/r
(9.8*.6)r=v^2
5.88*18=v^2
v=10.3 m/s My answer is said to be wrong