A diver springs upward with an initial speed of 1.7 m/s from a 3.0 m board. a. Find the velocity with which he strikes the water. (Hint: When the diver reaches the water, his displacement is y = -3.0 m (measured from the board), assuming that the downward direction is chosen as the negative direction.) b. What is the highest point he reaches above the water? I tried using this equation, but my answer was wrong. Can someone tell me what I did wrong? Part a: d=v*t + 1/2 at^2 -3.0=1.7t + 1/2(-9.80)t^2 4.9t^2 - 1.7t -3.0=0 t= 0.98s v=d/t v=3/0.98 v=3.06m/s I didn't do Part b because Part a was wrong!!