Physics hw

pwise2682

I already posted this but i think i may have a better idea how to do this.

Suppose 1.16g of pure gold has zero net charge. What would be its net charge after it has 1% of its electrons removed????

(1.16g/196.966 g/mol* 6.022E23* 1.602E-19 C) .99= 562.477 C

IS THAT RIGHT????

Related Introductory Physics Homework Help News on Phys.org

AKG

Homework Helper
If you remove X electrons, you remove a charge of (-1.602E-19 C)x. If the net charge is initially zero, it ends up being (1.602E-19 C)x. x = 0.01N, where N is the total number of electrons. N = pq, where p is the number of electrons that a gold atom has, and q is the number of gold atoms in 1.16g of pure gold. q = (m/M)A, where m = 1.16g is the mass of the gold, M is the molar mass of gold, and A is Avogadro's number, 6.022E23. I have a feeling your calculation is wrong. For one, I don't know why you're multiplying by 0.99 (you should be multplying by one minus 0.99). Also, you don't take into account the fact that gold atoms have more than one electron.

Physics Forums Values

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving