lilwigz said:The Attempt at a Solution
I used the equation Vf^2=Vi^2+2a(delta x)
Larry's Peach moves according to the laws of kinematics, which describe the motion of objects without taking into account the forces that cause the motion. In this experiment, the peach is initially at rest and then moves in a straight line with a constant velocity.
The velocity of Larry's Peach can be affected by the initial speed at which it is launched, the angle at which it is launched, and any external forces acting on it such as air resistance or gravity. In this experiment, we are assuming these factors are constant and the peach is moving in a vacuum.
The velocity of Larry's Peach can be calculated using the formula v = d/t, where v is velocity, d is distance, and t is time. In this experiment, the peach is launched at a known height and travels a known distance, so we can calculate its velocity by dividing the distance by the time it takes to travel that distance.
In this experiment, Larry's Peach moves with a constant velocity, which means it has no acceleration. This is because there are no external forces acting on the peach to cause it to accelerate or decelerate.
In this experiment, Larry's Peach moves in a straight line with a constant velocity, so it does not change its direction of motion. However, in other experiments where external forces are present, the peach may change its direction of motion due to the influence of those forces.