1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Physics Motion Help

  1. Feb 13, 2006 #1
    I'm having trouble with the 2nd part of this question, which asks at what instant the VAN (Green) overtakes the CAR (Red). I drew out the diagram. From what I believe, the displacements have to be equal so would I have to substitute two equations in each other?

    [​IMG]
     
  2. jcsd
  3. Feb 13, 2006 #2
    That's correct

    marlon
     
  4. Feb 13, 2006 #3
    I'm just lost on how to start the question...my friend and I are discussing it but bleh >_<
     
  5. Feb 13, 2006 #4
    Well write down the equation of v as a function of time t.

    You know that :
    (30,15) and (0,0)
    (60,20) and (0,0)

    are the couples of points that belong to each linear curve.

    Can you write down the equation of a linear function when these points have been given ?

    marlon
     
  6. Feb 13, 2006 #5
    well we're not supposed to use linear function...it's on agraph so it displacement would the area underneath the graph...still stuck on it.
     
  7. Feb 13, 2006 #6
    i don't think you are getting the point.

    Just set up v = a*t

    by using [tex]y-y1 = \frac{y2-y1}{x2-x2}(x-x1)[/tex]

    The (x1,y1) and (x2,y2) have been given. Keep in mind that x is t and y is v here

    Or you can indeed get the a by calculating the surface under the curve.

    Anyhow, the result must stay the same.

    marlon
     
  8. Feb 13, 2006 #7
    Omg I Figured It Out. Thank You Marlon!
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Physics Motion Help
Loading...