I was wondering if I may interprete AC current as a tranverse wave trough copper as medium. So this wave behaviour has a general wave-form written as: [tex]\zeta(x,t)=\zeta_{0}sin(kx-\omega.t)[/tex](adsbygoogle = window.adsbygoogle || []).push({});

This is a solution to the partial differential equation:

[tex]\frac{\partial^{2}\zeta}{\partial t^{2}}=K.\frac{\partial^{2}\zeta}{\partial x^{2}}[/tex]

K is the medium-depent factor, wich will determine the wave velocity.

Because the electric!ty will only be a one direction flow (assume we talk about a period in 50Hz current), the derivative to x direction wille be meaningless..I think.

But electricity is the flow of electrons, so the medium itself will be responsible for the wave. This bothers my whole perception of the above approach...

Anyway who shares same ideas?

grtz

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# Physics of AC electricity

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