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Physics of golf

  1. Mar 17, 2006 #1
    A golf ball is putted too fast and rolls past the hole in a straight line, coming at closest approach to a distance d from the hole. Ignore friction and assume that golf ball moves at constant velocity.
    What is the angular momentum of the golf ball about the hole?
    Is the angular momentum constant about this point?

    I belive that the angular momentum is constant but its direction changes due to an external torque. Yet the equation to use is beyond me could it be d(theta)=dL/L?
     
  2. jcsd
  3. Mar 17, 2006 #2
    Actually... When we say a golf ball has a constant velocity, all the forces must add up to be zero.

    Start with that by drawing components then doing a sum in the X and Y directions.
     
  4. Mar 17, 2006 #3

    Doc Al

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    Staff: Mentor

    Consider the definition of the angular momentum of a particle:
    [tex]\vec{L} = \vec{r} \times \vec{p}[/tex]
     
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