1. The problem statement, all variables and given/known data A 4,535,924-kg ship rests on launching ways that slope down to the water at an angle of 10 degrees. If the coefficient of sliding friction is 0.18, how much force is needed to winch the ship down the ways into the water? 2. Relevant equations Force of friction=μFn Force parallel = mgsinθ Force of friction in the y direction on an inclined plane = mgcosθ = Fn 3. The attempt at a solution My first step is to solve for the force of friction using the given angle, mass and gravity. Force of friction= (0.18)(4,535,924kg)(9.8 m/s^2)cos10°=7,879,811N Now this is where I become confused. The problem states that the ship "rests," so I solve for the net force, right? The force needed to move the ship must be greater than this net force, correct? Or should it just be greater than the frictional force that I solved for? ƩF=Fparallel - Force of friction =mgsin10° - 7,879,811N =7,719,018N - 7,879,811N=-160,973N Conclusion: My biggest problem is understanding what is required to make the ship move from rest. Comments and questions concerning my question would be appreciated.