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The work in joules required to carry a 6.0 C charge from a 5.0 V equipotential surface to a 6.0V equipotential surface and back again to the 5.0V surface is:
A) 0
B) 1.2 X 10^-5
C) 3.0 X 10^-5
D) 6.0 X 10^-5
E) 6.0X10^-6
Can someone please explain how to start off doing this problem. I thought that it involved the equation U= U2-U1= W. But, I am unsure how you connect the two.
Thank you
A) 0
B) 1.2 X 10^-5
C) 3.0 X 10^-5
D) 6.0 X 10^-5
E) 6.0X10^-6
Can someone please explain how to start off doing this problem. I thought that it involved the equation U= U2-U1= W. But, I am unsure how you connect the two.
Thank you