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Physics Practical: Check proportionality
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[QUOTE="Janiceleong26, post: 5200297, member: 564828"] [h2]Homework Statement [/h2] [ATTACH=full]87387[/ATTACH] [ATTACH=full]87388[/ATTACH] [ATTACH=full]87389[/ATTACH] For part d), how to show that they are inversely proportional to each other ? The mark scheme states: "Correct calculation to check inverse proportionality. √h x cosϑ = k. Sensible comments relating to calculations to within 20% or their own value and suggested relation." What do they mean by 20%? [h2]Homework Equations[/h2] Percentage uncertainty = (uncertainty/measured value) x100% [h2]The Attempt at a Solution[/h2] My values are, √h = (2.95±0.1) cm, cos θ = 0.50. k1 = 2.95 x 0.50 = 1.475 √h = (2.30±0.1) cm, cos θ = 0.64, k2 = 2.30 x 0.64 = 1.472 I calculated the percentage difference of k, ((1.475-1.472) /1.472 ) x 100% = 0.2% Then I calculated the uncertainty of √h = (0.1 / 2.30) x 100% = 4.3% This is the method I followed from a textbook, so what does the 20% in the mark scheme represents ? Hope you all understand what I'm doing here.. [/QUOTE]
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Physics Practical: Check proportionality
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