Physics Problem: Brick Thrown From Building Height

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A brick is thrown upward from the top of a builidng at an angle 25 degrees to the horizontal and with an initial speed of 15m/s. If the brick was in the air for three seconds how tall is the building
 
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giv this a try!

this probs is a projectile motion probs where the object is launched at an angle from horizontal surface. i wud rather u to c this probs in the first half of its motion. when the total time taken for the object to travel up to the height of the buildin and then come back to the position that it started from is 3 sec...it has ta take 1.5 sec to reach to the maximum height of the buildin where the y component of the velocity has to be 0. now when u divide the prob and solve it imaginin the first half...its much less complicated!
the initial y-velocity will be- 15 sin25= 6.3 m/s
to find the max height...we will use the formula- y= ut + .5 at^2
6.3(1.5)+.5 (9.8)(2.25)
=1.6 m
i will feel much better if the answer come out rite...if not we will try solvin it in other ways!
take care
 
doc...i havnt assumed that the ball lands on the buildin...just that it crosses the buildin! so when u consider just one part of the problem...where the ball moves up and reaches the highest point...u cud solve the probs in much easier way...try urself! i m sure it will make much more sense...
and thnx lettin me know the rules...appreciate that!
cheers!
 
ritz said:
doc...i havnt assumed that the ball lands on the buildin...just that it crosses the buildin!
Seems to me like you did. You said this:
ritz said:
when the total time taken for the object to travel up to the height of the buildin and then come back to the position that it started from is 3 sec
But that 3 sec total time must be the time for the brick to go from rooftop to highest point and then down to the ground, else the problem won't make sense. (The time it takes to get to the highest point is not 1.5 sec.)