# Physics problem: elevator force

An elevator (mass 4100 kg) is to be designed so that the maximum acceleration is 0.0700g.
What is the maximum force the motor should exert on the supporting cable?
What is the minimum force the motor should exert on the supporting cable?

I converted the acceleration to .6867 m/s^2 and plugged that and the mass into F=ma, but the answers doesn't seem to be right.

$$\begin{array}{cc} Newton's\ 2nd\ Law\\ \sum \vec{F}=m\vec{a}\\ F_{ec} + W =ma \ with \ a= \ The \ elevator's\ acceleration\\ F_{ec} + (-mg) = ma\\ F_{ec} = m(a+g)\\ F_{ec_max}= m(0.0700g+g)\ When\ a=+0.0700g\ ie\ The\ elevator \ accelerates\ upward\\ F_{ec_min}= m(-0.0700g+g)\ When\ a=-0.0700g\ ie\ The\ elevator \ accelerates\ downward\\ \end{array}$$