1. The problem statement, all variables and given/known data A duck has a mass of 2.5 kg. As the duck paddles, a force of the water exerts a force of 20.0 N in a direction of 52 degrees south of east. When these forces begin to act, the velocity of the duck is .11 m/s in a direction due east. Find the magnitude and direction ( relative to due east) of the displacement that the duck undergoes 3.0 s while the forces are acting. time=3.0s angle=52 degrees F=.20 N F=.10N Mass of duck=2.5 kg 2. Relevant equations Acos 52 degrees A sin 52 degrees x=Vox(t) + Ax (t)^2/ 2 3. The attempt at a solution I figured out the x component, and I got .20cos 52=.123 N Then I added .10 N + .123 =.223 N Then I figured out the acceleration .233 N/ 2.5 kg= .089 m/s^2 (if your getting a different answer then me it's because I rounded off, but I'm still using the exact numbers on my calculator such as .1231222951) Then I used that kinematic equation x= .11 m/s (3.0 s) + (.089 m/s^2) (3.0s)^2/2 = .7305 m In the back of my book the answer is .78 meters. What did I do wrong.