(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

In an attempt to escape a desert island, a castaway

builds a raft and sets out to sea. The wind shifts a great

deal during the day and he is blown along the following

directions: 2.50 km and 45.0° north of west, then 4.70 km

and 60.0° south of east, then 1.30 km and 25.0° south of

west, then 5.10 km straight east, then 1.70 km and 5.00°

east of north, then 7.20 km and 55.0° south of west, and

finally 2.80 km and 10.0° north of east. Use a graphical

method to find the castaway’s final position relative to the

island.

Ok so im just doing this for fun getting ready for the spring semester trying to get ahead.

So the book is giving me 7.34km and 63.5 SW im getting after multiple attempt 9.14km and 62.50SW

What am I doing wrong

3. The attempt at a solution

2.50km 45° NW is 135°

4.70km 60° SE is 300°

1.30km 25° SW is 205°

5.10km 0° E is 0°

1.70km 5° NE is 5°

7.20km 55° SW is 235°

2.80km 10° NE is 10°

---------------------------------------------------------

2.50cos(135) = -1.77

2.50sin(135) = 1.77

4.70cos(300) = 2.35

4.70sin (300) = 4.07

1.30cos(205) = -1.78

1.30sin(205) = -0.55

5.10cos(0) = 5.10

5.10sin(0) = 0

1.70cos(5) = 1.69

1.70sin(5) = 0.15

7.20cos(235) = -4.13

7.20sin(235) = -5.90

2.80cos(10) = 2.76

2.80sin(10) = 0.49

My answer is 4.22i - 8.11j 9.14km and 62.50SW

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# Homework Help: Physics Problem using Vectors

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