Physics problems

  • Thread starter prokoro
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  • #1
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Hello,

I'm doing this problem; a jet aircraft bein launch from an aircraft carrier acceleration from the rest along a 94m track for 2.5sec?

The problem is my answer is different from book

I am using the equation V=V 0 + at

V=94m
T=2.5sec

V=0+94m(2.5sec)=235m/s

I know this answer is wrong I suppose to be looking for the acceleration of the aircraft assuming constant.

I even tried to work this problem with the equation
V^2=V^20+2a(x-x)

thank-you
 

Answers and Replies

  • #2
5
0
Nevermind the above post

I figured out the correct answer to the problem V^2+V^2/2(x-x).

(2.5s)^2-(0)^2/2(94m)=30m/s
30m/s instead of the above answer
 
  • #3
HallsofIvy
Science Advisor
Homework Helper
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I'm glad you finally got it! For future reference, it would be good idea to tell us what the question is! I assume, although you didn't say it, that you are given the final speed and time and are asked what the acceleration is. By the way, you tell us that
V= 94 m which doesn't make sense: "meters" measures distance, not speed. 94 meters is the length of the track so you need to use the distance formula: d= 94= V0 t+ (a/2) t2.
V0= 0 and t= 2.5 so you can solve for a.
 

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