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Physics problems

  • Thread starter prokoro
  • Start date
5
0
Hello,

I'm doing this problem; a jet aircraft bein launch from an aircraft carrier acceleration from the rest along a 94m track for 2.5sec?

The problem is my answer is different from book

I am using the equation V=V 0 + at

V=94m
T=2.5sec

V=0+94m(2.5sec)=235m/s

I know this answer is wrong I suppose to be looking for the acceleration of the aircraft assuming constant.

I even tried to work this problem with the equation
V^2=V^20+2a(x-x)

thank-you
 
5
0
Nevermind the above post

I figured out the correct answer to the problem V^2+V^2/2(x-x).

(2.5s)^2-(0)^2/2(94m)=30m/s
30m/s instead of the above answer
 

HallsofIvy

Science Advisor
Homework Helper
41,712
876
I'm glad you finally got it! For future reference, it would be good idea to tell us what the question is! I assume, although you didn't say it, that you are given the final speed and time and are asked what the acceleration is. By the way, you tell us that
V= 94 m which doesn't make sense: "meters" measures distance, not speed. 94 meters is the length of the track so you need to use the distance formula: d= 94= V0 t+ (a/2) t2.
V0= 0 and t= 2.5 so you can solve for a.
 

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