jarrellboog04 said:A rifle is aimed horizontally at a target 50m away. The bullet hits the target 2.0cm below the aim point.
A. What was the bullet's fight time?
B. What was the bullet's speed as it left the barrel?
Please HELP!
jarrellboog04 said:It does not give me the time
jarrellboog04 said:None of those are the equations i have for the problem i have the answer from the back of the book but that does not help if i do not no how to answer it i tried many differnet ways but still can not find the right way
jarrellboog04 said:i changed the 2cm to .02m to get the same units
jarrellboog04 said:I did conversion. I jus figured out the answer to part a i got .064s
i used the equarition
y^f=y^i + (v^y)i delta (t)-1/2g(delta (t)2
jarrellboog04 said:But now i am trying do part b but cant
jarrellboog04 said:I am going to use this equation and see if i can figure it out
x^f=x^i+(v^x)i delta (t)
jarrellboog04 said:i got Xi to be .02m
jarrellboog04 said:u still can not figure it out
Projectile motion is the motion of an object that is thrown or launched into the air and then moves under the force of gravity. It is a combination of horizontal and vertical motion, with the horizontal motion remaining constant and the vertical motion being affected by the force of gravity.
The flight time of a projectile can be calculated using the equation t = 2 * V * sin(theta) / g, where t is the flight time, V is the initial velocity, theta is the angle of launch, and g is the acceleration due to gravity (9.8 m/s^2).
The initial velocity in projectile motion is the velocity at which the object is launched or thrown into the air. It has both horizontal and vertical components, and can be calculated using the equation V = sqrt(Vx^2 + Vy^2), where Vx is the initial horizontal velocity and Vy is the initial vertical velocity.
Air resistance, or drag, can affect the flight of a projectile by slowing it down and changing its trajectory. This is because air resistance creates a force in the opposite direction of the projectile's motion, which decreases its velocity. However, air resistance is usually negligible for most projectile motion calculations.
The maximum height of a projectile is the highest point it reaches during its flight. It can be calculated using the equation h = (Vy^2 / 2g), where h is the maximum height, Vy is the initial vertical velocity, and g is the acceleration due to gravity. The maximum height is also equal to the vertical displacement at the peak of the projectile's trajectory.