1. The problem statement, all variables and given/known data The constant force that works in the object M=5 kg forces the object with mass m=4 kg to move with acceleration a=2 m/s^2. The coefficient of friction between M and the table is 0.2. Determine a)F=? b) T=? 2. Relevant equations 3. The attempt at a solution SOLUTION: F-Ff=(m)*a Here I find F and here I find F B) F-(T+Ff)=m*a or T=m2*g ;G-T=m*g Picture to help you http://i1171.photobucket.com/albums/r549/Elaia06/jh.jpg [Broken] Edited: Maybe it is F-Ff=(m+M)*a where Ff =M*g*0.2?