Hi!! I'm have difficulty with this question. If anyone can help it would be a lot of help.(adsbygoogle = window.adsbygoogle || []).push({});

Problem

Raj is late for the bus, and as he closes the door to his house, he notices the bus, located 25m away, has begun to accelerate away from him at 1.0 m/s^{2}. Raj begins to chase the bus immediately at a speed of 3.4 m/s. Is Raj able to catch the bus? If he does, where does he catch up to it? If he does not, calculate Raj's frustration distance.

What I've tried to solve

d_{bus}= d_{raj}

1/2(v)t^{2}= vt

1/2(1.0)t^{2}= 3.4t

0=-1/2t^{2 }+ 3.4 t

Used quadratic formula to get

t = -0.25 OR t = 7.08

But at 7.08s Raj is no where near the bus because it takes him 7.352 seconds to reach 25m the distance the bus was originally from Raj...

It doesn't make any sense!!

Another question

What is frustration distance? and how can it be calculated?

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# Homework Help: Physics question help catching bus

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