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**1. Homework Statement**

A two-stage rocket is travelling at 1192.0 m/s with respect to the earth when the first stage runs out of fuel. Explosive bolts release the first stage and push it backward with a speed of 32.4 m/s relative to the second stage. The first stage is 2.00 times as massive as the second stage. What is the speed of the second stage after the separation?

**2. Homework Equations**

Conversation of momentum.

**3. The Attempt at a Solution**

I first set the second stage's mass as "m". The mass of the first stage then would be "2m" and the total rocket would have a mass of "3m".

Using the conservation of momentum I made an equation:

momentum of first stage+momentum of second stage= momentum of the rocket

(-32.4)*(2m) + v(m) = 1192(3m)

the m's cancel out and I solved for v:

3,640.8 m/s

however this does not match the answer in my textbook.... :/

Thanks in advanced.