- #1

MozAngeles

- 101

- 0

## Homework Statement

The Bohr Atom The Bohr model of the hydrogen atom pictures the electron as a tiny particle moving in a circular orbit about a stationary proton. In the lowest-energy orbit the distance from the proton to the electron is 5.29 * 10^- 11 m, and the linear speed of the electron is 2.18 *10^6 m/s.

A. What is the angular speed of the electron?

**got it.. [tex]\omega[/tex] =4.12×10^ 16 rad/s**

**B. How many orbits about the proton does it make each second? ??**

## Homework Equations

omega=linear velocity/radius

1rev=2[tex]\pi[/tex] rad

## The Attempt at a Solution

you would think you would just divide the result from question A (4.12*10^16 rad per s) by the conversion factor of rev to rad (2[tex]\pi[/tex]). However, this is showing up to be wrong on the website.. I have no idea of what else i can do...