Physics, rotational kinematics

[MozAngeles]

Homework Statement

The Bohr Atom The Bohr model of the hydrogen atom pictures the electron as a tiny particle moving in a circular orbit about a stationary proton. In the lowest-energy orbit the distance from the proton to the electron is 5.29 * 10^- 11 m, and the linear speed of the electron is 2.18 *10^6 m/s.
A. What is the angular speed of the electron? got it.. $$\omega$$ =4.12×10^ 16 rad/s

B. How many orbits about the proton does it make each second? ??

Homework Equations

omega=linear velocity/radius
1rev=2$$\pi$$ rad

The Attempt at a Solution

you would think you would just divide the result from question A (4.12*10^16 rad per s) by the conversion factor of rev to rad (2$$\pi$$). However, this is showing up to be wrong on the website.. I have no idea of what else i can do...

 

[tiny-tim]

Hi MozAngeles!

(have a pi: π and an omega: ω and try using the X² tag just above the Reply box )

you would think you would just divide the result from question A (4.12*10^16 rad per s) by the conversion factor of rev to rad (2$$\pi$$). However, this is showing up to be wrong on the website.. I have no idea of what else i can do...

Looks ok to me.