Alright well the problem is that 10 kg frozen turkey is thrown and goes horizontally on a surface with a 0.10 coefficient of kinetic friction. It travels for 10 meters. What is the work the friction does to stop the object. And what is the speed the frozen turkey is thrown at?
W=f * d
The Attempt at a Solution
I did the problem I don't know if it is right, I am hoping you guys will tell me if I did.
First I got the weight of the turkey.
10 kg * 9.81 m/s^2 = 98.1 N downward
Then 98.1N * Coefficient of .10 = 9.81 N kinetic friction.
Then plugged that into the work equation W=9.81 * 10 meters = so I got the work
of friction to be 98.1 Joules.
Then to find the speed I did
98.1 joules = 10*v^2/2 then got it to equal 4.43 m/s. did I do these steps right? If not can somebody help me? Thanks.