1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Physics work question

  1. Apr 14, 2013 #1
    1. The problem statement, all variables and given/known data
    A 25.6 kg child pulls a 4.81kg toboggan up a hill inclined at 25.7 degrees to the horizontal. The vertical height of the hill is 27.3 m. Friction is negligible.

    Determine the amount of work the child must do on the toboggan to pull it at a constant velocity up the hill.


    2. Relevant equations
    W = F * D


    3. The attempt at a solution
    ag = gravity component of acceleration
    ap = acceleration applied

    ag - ap = 0
    ag = 9.81 m/s^2 * cos(25.7 deg) = 8.8 m/s/s

    F = 8.8 m/s/s * 4.81 kg = 42.5 N

    W = F * D = 42.5 N * (27.3 m / (sin(25.8 deg)) = 2 665.82513 joules

    This answer is completely wrong. The book got 1.3 * 10 ^ 3 J.

    Not sure what I can do, I thought about setting W = Eg2 - Eg1. But I remember my teacher said that only works for kinetic energy (honestly, sometimes I think she doesn't know what shes talking about. It should work for gravitational energy too)

    But if I do that,

    W = 4.8 kg * 9.8 m/s^2 * 27.3 m I get the right answer which is 1 284.192 joules

    This is confusing for me. Shouldn't I have gotten the same answers for both questions? How come my answers are different? Does it have something to do with vectors? Does work only count in one direction in this case (vertical), shouldn't the work done be how I calculated it in step 1?

    More importantly, can I set W = change in energy, even if that energy is NOT kinetic?
     
  2. jcsd
  3. Apr 14, 2013 #2
    Both methods would work. Your math is off in the first one, though: It should be sin(25.7°), not cos(25.7°). You're looking for the parallel part of ag, not the perpindicular part.
     
  4. Apr 14, 2013 #3

    PhanthomJay

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member

    you may have misunderstood your teacher. The TOTAL work done by ALL forces is equal to the change in kinetic energy. This includes work done by conservative forces (like gravity) and non conservative forces (like applied forces). The work done by only nonconservative forces is equal to the change in kinetic plus potential energy.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Physics work question
Loading...