Two figure skaters, one weighing 675 N and the other 750 N, push off against each other on very smooth ice.(adsbygoogle = window.adsbygoogle || []).push({});

1. If the heavier skater travels at 1.20 m/s, how fast will the lighter one travel?

2. How much kinetic energy is "created" during the skaters' maneuver?

3. Where does this energy come from?

is this right....

1. Conservation of momentum

Momentum of heavier skater = 1.2*750 = 900kgm/s

Velocity of lighter skater = 900/675 = 1.33m/s

2. KE of heavier = 1/2*m*v^2 = 0.5*750*1.2^2 = 540J

KE of lighter = 0.5 * 675 * 1.3^2 = 600J

Total KE = 1140J

3. It is created from the energy the two skaters use to push away from each other

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# Homework Help: Phywic hw please help

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