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I was wondering if this reactions is possible:

[tex]\pi^{+} + n \rightarrow p + \gamma[/tex]

(Assuming there is enough energy in the initial state to make the reaction go)

If not, what law is violated?

Lepton and baryon numbers are ok... also angular momentum, so I guess it's possible, but still... I can't figure out how to draw the feynman diagram, since there is a total of 5 quarks in the initial state ([tex] u,\bar{d}... d,d,u [/tex]) and there is just 3 in the final state (u,u,d and gamma).

At first, I was thinking in merging d and [tex]\bar{d}[/tex] into a photon , but just 1 photon would violate the momentum conservation law...

Any ideas?

Thanks

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# (pi+)(n)-> (p)(gamma)

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