Use picard iteration 4 times to estimate the initial value problem solution: y' = 2xy thru (0,1) First off, when it says thru (0,1), I am assuming it means y(0) = 1. I was not sure if I was doing picard iteration right, but here it my attempt: dy/dx = 2xy dy/y = 2x dx dy/1 = 2x dx - since y(0) = 1 y = x^2 + C so y = x^2 + 1. This is the first iteration y' = x^2 + 1. So now I just solve this ........ and so on 4 times. Or is picard iteration work like this: dy/dx = 2xy dy/y = 2x dx ln|y| = x^2 + C y = e(x^2 + C) y = e^(x^2)e^(C) y = Ce^(x^2) when y(0) = 1, C = 1 So y = e^(x^2) This is the first iteration So then I integrate and repeat this 3 more times. I wasnt sure which one was the right way to do picard iteration or if neither way is right.